We will solve as follows:


So, the solution is x < -3.
***Breakdown:
*After we obtain:

We operate like terms, that is we separate the variables and integers in the different side [Operating as if it were a normal equation]:

After this, we know that by dividing and/or multiplying by negative values in the inequality the orientation of the inequality will shift [That is if it was "<" then it will become ">" and viceversa], that is:
