Question

Can u help me with this by using inverse trig.ratios. Find angle A and angle B.

Answer 1

The hypotenuse is 39 because is opposite to the angle of 90 degrees.

So, angle A is given by

`\measuredangle A=\sin ^(-1)(7)/(39)`

Then, we have

`\measuredangle A=\sin ^(-1)(0.17948)`

which gives

`\measuredangle A=10.339\text{ degre}es`

Now, angle C is equal to 90 degrees and angle B is given by

`\begin{gathered} \measuredangle B=\cos ^(-1)((7)/(39)) \\ \measuredangle B=\cos ^(-1)(0.17948) \\ \measuredangle B=79.66\text{ degr}ees \end{gathered}`

Therefore, the answer is

`\begin{gathered} \measuredangle A=10.339\text{ degre}es \\ \measuredangle B=79.669\text{ degre}es \\ \measuredangle C=90\text{ degre}es \end{gathered}`