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Can u help me with this by using inverse trig.ratios. Find angle A and angle B.

Can u help me with this by using inverse trig.ratios. Find angle A and angle B.-example-1
User Lcl
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1 Answer

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The hypotenuse is 39 because is opposite to the angle of 90 degrees.

So, angle A is given by


\measuredangle A=\sin ^(-1)(7)/(39)

Then, we have


\measuredangle A=\sin ^(-1)(0.17948)

which gives


\measuredangle A=10.339\text{ degre}es

Now, angle C is equal to 90 degrees and angle B is given by


\begin{gathered} \measuredangle B=\cos ^(-1)((7)/(39)) \\ \measuredangle B=\cos ^(-1)(0.17948) \\ \measuredangle B=79.66\text{ degr}ees \end{gathered}

Therefore, the answer is


\begin{gathered} \measuredangle A=10.339\text{ degre}es \\ \measuredangle B=79.669\text{ degre}es \\ \measuredangle C=90\text{ degre}es \end{gathered}

User Nitesh Goel
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