Question

Out of 50 students, 17 want pepperoni pizza, 19 want sausage pizza and the rest want a supreme pizza. What percent of the students want a supreme pizza?

Answer 1

First, lets find how many students want the supreme pizza. Let 'x' be the number of those students. Then, given the information, we have:

`x+17+19=50`

solving for 'x', we get:

`\begin{gathered} x+17+19=50 \\ \Rightarrow x+36=50 \\ \Rightarrow x=50-36=14 \\ x=14 \end{gathered}`

we have that x = 14 students want a supreme pizza.

Now, if we suppose that the 50 students are the 100%, then, using a rule of three, we get:

`\begin{gathered} 50\rightarrow100\% \\ 14\rightarrow y\% \\ \Rightarrow y=(14\cdot100)/(50)=(1400)/(50)=28 \\ y=28\% \end{gathered}`

therefore, 28% of the students want a supreme pizza