We want to plot the graph of the equation;

we can do this by assuming to different values of x and deriving the corresponding values of y at those points.
for x= -4;

Also taking a second point.
at x = 0;

Since the equation is a linear equation, the graph will be a straight line graph;
the graph will be a straight lin passing through the two points derived.

the graph of the given equation can be shown below;