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What is[OH-] of a solution
with a pH of 11.3?

Answer in M

User Ygee
by
3.0k points

1 Answer

7 votes
7 votes

Answer:

2 ×10^-3

Step-by-step explanation:

pH + pOH = 14

pOH = 14-11.3 = 2.7

[OH-] = 10^-pOH = 10^-2.7 = 2×10^-3 M

User Arnaud Rinquin
by
3.4k points