-2880 Watts
Step-by-step explanation
Step 1
Let
![\begin{gathered} V=24V \\ Internal\text{ resistance of battery=}0.3\Omega \\ \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/2y5mgjxenp6ul782t0lhrjz501fcemy1wi.png)
Now, we need aplly the formula
![I(current\text{ in circuit)=}\frac{e.m.f}{\text{total resistance}}=\frac{24\text{v}}{0.3\Omega}=80\text{ Ampers}](https://img.qammunity.org/2023/formulas/physics/college/yr69ez00j0wb23qq0kp6a2jc7kamxcikse.png)
Step 2
now, we need to find the powe delivered, to do that, let's use this formula:
The power delivered by the voltage source is: PV = – I * V =
![\begin{gathered} P=-I\cdot V \\ P=-80\text{ A}\cdot(36)V \\ P=-2880\text{W} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/nnqft7qffmtfbbvoou7xuutn740nbqg3ud.png)
hence the answer is -2880 Watt
I hope this helps you
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