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Evaluate the function when x= -2,0, and 5 h(x)= -2x+9

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Given:

a function is given as h(x) = -2x + 9

Find:

we have to evaluate the function at x = -2 , 0 and 5.

Step-by-step explanation:

when x = -2

h(-2) = -2(-2) + 9 = 4 + 9 = 13

when x = 0

h(0) = -2(0) + 9 = 0 + 9 = 9

when x = 5

h(5) = -2(5) + 9 = - 10 + 9 = -1

Therefore, the values of given function h(x) are 13, 9 , -1 at x = -2, 0 , 5 respectively.

User CJ Zougloub
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