Given,
The coefficient of friction between the wheel and the road, μ=0.4
The radius of curvature of the road, r=100 m
The centripetal force for the cyclist to move in the curved path is provided by the friction between the road and the wheel.
Thus,
![\begin{gathered} (mv^2)/(r)=\mu mg \\ \Rightarrow v^2=r\mu g \\ v=\sqrt[]{r\mu g} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/lthanizlffb9zcgw7t5bd2yhkio362lvj8.png)
Where m is the mass of the cyclist and the cycle and g is the acceleration due to gravity.