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Hetepeperfan · Answer 1 · 2023-07-11T19:27:22+0000

hello

to solve this question, we simply need to apply the formula of area of a segment

the formula is given as

$A_{\text{segment}}=(1)/(2)*(\theta-\sin \theta)* r^2$

let's write out the variables given in the question

$\begin{gathered} \theta=60^0 \\ r=5\operatorname{cm} \end{gathered}$

we can now input those values into the equation

$\begin{gathered} A_{\text{segment}}=(1)/(2)*(\theta-\sin \theta)* r^2 \\ A_{\text{segment}}=(1)/(2)*(60-\sin 60)*5^2 \\ A_{\text{segment}}=(1)/(2)*(60-0.8660)*25 \\ A_{\text{segment}}=(1)/(2)*1478.35 \\ A_{\text{segement}}=739.175\operatorname{cm}^2 \end{gathered}$

to get the value of the area of the shaded region,

$\text{area of shaded region=area of circle - area of segment}$

let's calculate the area of the circle

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