72 ergs
Step-by-step explanation
Step 1
Kinetic energy varies jointly as the mass and the square of the velocity,then

where
m is the mass, v is the velocity and

A mass of 8 grams and velocity of 3 centimeters per second has a kinetic energy of 36 ergs

so, the equation is

Step 2
now , we know the equation to find the kinetic energy of a object if we know its mass and its velocity
Let
mass= 4 grams
velocity = 6 cms per sec
then
![\begin{gathered} E_k=(1)/(2)\cdot m\cdot v^2 \\ E_k=(1)/(2)\cdot4gr\cdot(6\frac{\operatorname{cm}}{\sec})^2 \\ E_k=(1)/(2)\cdot4gr\cdot36\frac{\operatorname{cm}}{\sec ^2} \\ E_k=72\text{ erg} \end{gathered}]()
I hope this helps you