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Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 8 grams and velocity of 3 centimeters per second has a kinetic energy of 36 ergs. Find the kinetic energy for a mass of 4 grams and a velocity of 6 centimeters per second.

User Jhvaras
by
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1 Answer

5 votes

72 ergs

Step-by-step explanation

Step 1

Kinetic energy varies jointly as the mass and the square of the velocity,then


E_k=\lambda\cdot m\cdot v^2

where

m is the mass, v is the velocity and


\lambda\text{ is a constant}

A mass of 8 grams and velocity of 3 centimeters per second has a kinetic energy of 36 ergs


\begin{gathered} E_k=\lambda m\cdot v^2 \\ 36\text{ erg=}\lambda\cdot8\cdot3^2 \\ 36=\lambda\cdot8\cdot9 \\ 36=\lambda\cdot72 \\ \text{divide both sides by 72} \\ (36)/(72)=\lambda \\ \lambda=(1)/(2) \end{gathered}

so, the equation is


\begin{gathered} E_k=\lambda\cdot m\cdot v^2 \\ E_k=(1)/(2)\cdot m\cdot v^2 \end{gathered}

Step 2

now , we know the equation to find the kinetic energy of a object if we know its mass and its velocity

Let

mass= 4 grams

velocity = 6 cms per sec

then


\begin{gathered} E_k=(1)/(2)\cdot m\cdot v^2 \\ E_k=(1)/(2)\cdot4gr\cdot(6\frac{\operatorname{cm}}{\sec})^2 \\ E_k=(1)/(2)\cdot4gr\cdot36\frac{\operatorname{cm}}{\sec ^2} \\ E_k=72\text{ erg} \end{gathered}

I hope this helps you

User Gabriele Mariotti
by
7.6k points
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