ANSWER:
6 gallons regular gas with 10% ethanol and 4 gallons E85 fuel with 85% ethanol
Explanation:
In this case, we must test with values for each fuel class to arrive at the correct answer.
For example, 6 gallons of 10% ethanol and 4 gallons of 85% ethanol:
![\begin{gathered} 10\text{\% of 6 =}(10)/(100)\cdot6=0.6\text{ gallons of ethanol in it} \\ 85\text{\% of 4 =}(85)/(100)\cdot4=3.4\text{ gallons of ethanol in it} \\ \text{ Total ethanol in 10 gallons is 0.6 + 3.4 = 4 gallons }\rightarrow\text{ 4 gallons is 40\% of 10} \\ \text{Therefore, we have 10 gallons of fuel containing 40\% ethanol } \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yrq19wn2u88dneuk92bmd6fm9tnni8tc67.png)