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Determine the minimum and maximum value of the following trigonometric function.

f(x)=10sin(2/5x)+5

Determine the minimum and maximum value of the following trigonometric function. f-example-1

1 Answer

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ANSWER


\begin{gathered} Minimum=-5 \\ Maximum=15 \end{gathered}

Step-by-step explanation

The trigonometric function given is:


f(x)=10\sin ((2)/(5)x)+5

The minimum value a sine function can take is -1.

This means that the minimum value of the function is:


\begin{gathered} 10(-1)+5 \\ \Rightarrow-10+5 \\ \Rightarrow-5 \end{gathered}

The maximum value a sine function can take is 1.

This means that the maximum value of the function is:


\begin{gathered} 10(1)+5 \\ \Rightarrow10+5 \\ \Rightarrow15 \end{gathered}

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