Question

A new cell tower is being constructed and needs a guy-wire connected 137 feet up the tower and it needs to make an angle of 56° with the ground. What length does the wire need to be?

Answer 1

`\begin{gathered} \sin (56)=\frac{137}{wire´s\text{ length}} \\ wire´s\text{ length=}(137)/(\sin(56)) \\ wire´s\text{ length=165.25fe}et \\ the\text{ wires length is 165.25 fe}et \end{gathered}`