Question

Hi! I need help with a couple math questions but heres this oneTriangle XYZ is located at X (−2, 1), Y (−4, −3), and Z (0, −2). The triangle is then transformed using the rule (x−1, y+3) to form the image X'Y'Z'. What are the new coordinates of X', Y', and Z'?

Answer 1

Transformation rule:

`(x,y)\rightarrow(x-1,y+3)`

Given triangle XYZ

To get X'Y'Z' coordinates of vertices, subtract 1 to the x coordinate and add 3 to the y-coordinate:

`\begin{gathered} X(-2,1)\rightarrow X^(\prime)(-2-1,1+3) \\ X^(\prime)(-3,4) \end{gathered}`
`\begin{gathered} Y(-4,-3)\rightarrow Y^(\prime)(-4-1,-3+3) \\ Y^(\prime)(-5,0) \end{gathered}`
`\begin{gathered} Z(0,-2)\rightarrow Z^(\prime)(0-1,-2+3) \\ Z^(\prime)(-1,1) \end{gathered}`Then, the coordinates of vertices in triangle X'Y'Z' are: X'(-3,4), Y'(-5,0) and Z'(-1,1)