Question

Find the equivalent resistance of thiscircuit.R₁www400 ΩIR₂600 ΩReq = [?] 2R3www500 Ω

Answer 1

We are given the following information.

Resistor: R₁ = 400 Ω

Resistor: R₂ = 600 Ω

Resistor: R₃ = 500 Ω

We are asked to find the equivalent resistance of the given circuit.

Notice that the resistors R₁ and R₂ are in parallel and this parallel combination is in series with resistor R₃.

First, let us find the parallel resistance of R₁ and R₂.

`R_p=(R_1* R_2)/(R_1+R_2)=(400*600)/(400+600)=(240000)/(1000)=240\;\Omega`

Finally, let us find the series resistance of Rp and R₃.

`\begin{gathered} R_(eq)=R_p+R_3 \\ R_(eq)=240+500 \\ R_(eq)=740\;\Omega \end{gathered}`

Therefore, the equivalent resistance of the given circuit is 740 Ω.