Question

Suppose a binomial trial has a probability of success of 0.3 and 450 trials are performed. What is the standard deviation of the possible outcomes?6.3614.8511.629.72

Answer 1

The standard deviation of a binomial distribution with n trials and a probability of success of p is given by the formula:

`\sigma=\sqrt[]{n\cdot p\cdot(1-p)}`

From the problem, we identify:

`\begin{gathered} n=450 \\ p=0.3 \end{gathered}`

Then:

`\begin{gathered} \sigma=\sqrt[]{450\cdot0.3\cdot(1-0.3)}=\sqrt[]{450\cdot0.3\cdot0.7} \\ \sigma\approx9.72 \end{gathered}`