Question

An object is placed 3.00 cm in front of a concave lens with a focal length of 5.00 cm. Find the image distance.

Answer 1

Step-by-step explanation:

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Answer 2

-1.88 cm

STEP-BY-STEP EXPLANATION:

The situation would be the following:

Given:

Object distance (u): -3 cm

Focal distance (f): -5 cm

Using the lens formula, we calculate the distance of the image:

`\begin{gathered} (1)/(v)-(1)/(u)=(1)/(f) \\ \\ \text{We replacing} \\ \\ (1)/(v)-(1)/(-3)=(1)/(-5) \\ \\ (1)/(v)\cdot \:15v-(1)/(-3)\cdot \:15v=(1)/(-5)\cdot \:15v \\ \\ 15+5v=-3v \\ \\ 5v=-3v-15 \\ \\ 8v=-15 \\ \\ v=-(15)/(8) \\ \\ v=-1.88\text{ cm} \end{gathered}`

The image distance is -1.88 cm