Question

Solve the following equation for and y - 3 - 7i + 6x = 19 + 2i + 13yi

Answer 1

Okay, here we have this:

Considering the provided equation, we are going to solve it, so we obtain the following:

`\begin{gathered} -3-7i+6x=19+2i+13yi \\ (-3+6x)-7i=19+(2+13y)i \end{gathered}`

So let's remember that a set of complex numbers can only be equal if their real and imaginary parts are equal. According to this we have:

-3+6x=19, -7=2+13y

6x=19+3, -7-2=13y

6x=22, -9=13y

x=22/6, y=-9/13

x=11/3, y=-9/13

Finally we obtain the following set: x=11/3, y=-9/13.