Question

For 97.1 seconds, a remote-controlled helicopter flew at an altitude of 3 meters and a constant velocity of 19.0 meters per second to the west. During this time, how far did the helicopter fly?

Answer 1

The relationship between time, distance and velocity is:

`v=(d)/(t)`

In this case, we need to find the distance, d

We can solve for d:

`v=(d)/(t)\Rightarrow d=v\cdot t`

The velocity of flight is v = 19 m/s and the time of flight is t = 97.1s

Then:

`d=19(m)/(s)\cdot97s`
`d=1844.9m`

The answer is 1844.9m