Question

On a coordinate plane, point J is located at (-1, units, from point J to point K? 2) and point K is located at (8, 10). What is the distance, in Enter your answer in the space provided.

Answer 1

The expression for the distance between two coordinates are express as :

`\text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`

Substitute the values of the coordinates:

`\begin{gathered} (x_1,y_1)=(-1,-2) \\ (x_2,y_2)=(8,10) \end{gathered}`

`\begin{gathered} \text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{Distance}=\sqrt[]{(8-(-1))^2+(10-(-2))^2} \\ \text{Distance}=\sqrt[]{(8+1)^2+(10+2)^2} \\ \text{Distance}=\sqrt[]{9^2+12^2} \\ \text{Distance}=\sqrt[]{81+144} \\ \text{Distance}=\sqrt[]{225} \\ \text{Distance}=15\text{ unit} \end{gathered}`

So, distance between two points (-1,-2) & (8,10) is 15

Answer : Distance between two points (-1,-2) & (8,10) is 15.