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A toy that Is 0.5 ft long is used to model the actions of an actual car that is 15 ft long. Which ratio shows the relationship between the sizes of the model and the actual car????

User Natanya
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1 Answer

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The length of the toy is,


l=0.5\text{ ft}

The actual length is given as,


l^(\prime)=15\text{ ft}

The ratio of these two values is,


\begin{gathered} (l)/(l^(\prime))=(0.5)/(15) \\ (l)/(l^(\prime))=(1)/(30) \end{gathered}

Thus, the model is 1/30 times size of an actual car.

User Horia Toma
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