Question

If a solution contained a substance of 4.67kg (molar mass of 34.6 g/mol) in 350mL, what is the molarity of the solution?

Answer 1

The molarity of a solution is the molar concentration of it.

It is calculated by:

`M=(n)/(V)`

Where n is the number of moles of the substance in the solution and V is the total volume of the solution.

The volume was given:

`V=350mL=0.350L`

And the number of moles we can calculate using the given mass and the molar mass:

So:

`\begin{gathered} MM=(m)/(n) \\ n=(m)/(MM)=(4670g)/(34.6g/mol)=134.97\ldots mol \end{gathered}`
`M=(134.97\ldots mol)/(0.350L)=385.63\ldots mol/L\approx386mol/L`

Thus, the molarity is approximately 386 mol/L.