Question

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=40°, and QO = 3.1 feet. Find the length of PQ to the nearest tenth of a foot. PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

2.6feet

Explanation:

The angle opposite to PQ is m<O

Opposite side = PQ

Adjacent side = QO

Using the SOH CAH TOA identity

Tan theta = Opposite/Adjacent

Tan 40 = PQ/QO

Tan 40 = PQ/3.1

PQ = 3.1tan40

PQ = 3.1(0.8391)

PQ = 2.6feet