Question

A sample of silver at 10°C is heated to 90°C when 1 kcal of heat is added. What is the mass of the silver?

Answer 1

We can use the following formula:

`q=m\cdot c\cdot(T2-T1)`

Where:

q = heat = 1 kcal = 4184000J

c = specific heat (of silver) = 0.235 J °C /g

m = mass

T1 = Initial temperature = 10°C

T2 = Final temperature = 90°C

Therefore, solve for m:

`\begin{gathered} m=(q)/(c(T2-T1)) \\ m=(4184000)/(0.235(90-10)) \\ m=222553.1915g \end{gathered}`

Answer:

222553.1915g