212k views
4 votes
A battery does 1.922 J of work to transfer 0.089 C of charge from the negative to the positive terminal. What is the emf of this battery?

User Pdrcabrod
by
4.8k points

1 Answer

4 votes

We can find the EMF as follows:


\begin{gathered} EMF=(W)/(q) \\ where: \\ W=1.922J \\ q=0.089C \\ so: \\ EMF=(1.922)/(0.089) \\ EMF=21.5955V \end{gathered}

Answer:

21.5955V

User AchillesVan
by
5.5k points