Question

A battery does 1.922 J of work to transfer 0.089 C of charge from the negative to the positive terminal. What is the emf of this battery?

Answer 1

We can find the EMF as follows:

`\begin{gathered} EMF=(W)/(q) \\ where: \\ W=1.922J \\ q=0.089C \\ so: \\ EMF=(1.922)/(0.089) \\ EMF=21.5955V \end{gathered}`

Answer:

21.5955V