Question

Howmany molecules of iron (iii) oxide canbe produced from 13.5 molesFe

Answer 1

Answer: 8.1297x10^24 molecules

Calculations:

Balanced Reaction :

`2Fe+3O_2\Rightarrow2Fe_2O_3`

1. by stoichiometry,

• 2 moles of Fe : 2 moles of iron (iii) oxide

• then 13.5 moles Fe : x

X = 13.5 *2 /2 = 13.5 moles of Fe

• This means that 13.5 mole of Fe2O3 will be produce.

2. Calculate number of molecules by Avogardo principles.

No. of molecules = Moles * Avogardo Number

`\begin{gathered} Fe_2O_{3\text{ }}Molecules\text{ = 13.5 moles }\cdot6.022\cdot10^(23) \\ \text{=8.1297}\cdot10^(24) \end{gathered}`

• This means that there are 8.1297 x10^24molecules of Fe2O3 from 13.5 moles Fe.