Question

Calculate the pH and pOH of aqueous solutions with the following concentrations.[OH﹘] = 1.0 x 10-7M

Answer 1

Answer;

pH = 7

pOH = 7

Explanations:

The formula for calculating the pOH of a solution is given as:

`pOH=-log[OH^-]`

Given the following parameter

`[OH^-]=1.0*10^(-7)M`

Substitute

`\begin{gathered} pOH=-log(1.0*10^(-7)) \\ pOH=-log(10^(-7)) \\ pOH=-(-7) \\ pOH=7 \end{gathered}`

Determine the pH of the solution

Recall that pH + pOH = 14, hence;

`\begin{gathered} pH=14-pOH \\ pH=14-7 \\ pH=7 \end{gathered}`

Hence the required pH and pOH of aqueous solution are 7 and 7 respectively