Question

what is slope of the line parallel to the given line(I know the steps no explanation just need work:)

Answer 1

Given the equation of the line :

`4x-3y=-12`

To find the slope, solve the equation for y:

`\begin{gathered} 4x-3y=-12 \\ -3y=-4x-12 \end{gathered}`

Divide both sides by -3 :

`\begin{gathered} (-3y)/(-3)=(-4x)/(-3)-(12)/(-3) \\ \\ y=(4)/(3)x+4 \end{gathered}`

So, the slope of the given line = 4/3

And the slope of the line parallel to the given line = 4/3

Because the parallel line have the same slopes

So, the answer is : slope = 4/3