3.4k views
4 votes
Consider the following compound inequality. 2x+3_<5 or 4x+1>17A)Solve the inequality for x.B) Graph the compound inequality. C) Enter the solution in interval notation.

Consider the following compound inequality. 2x+3_<5 or 4x+1>17A)Solve the inequality-example-1
User Keneisha
by
4.9k points

1 Answer

0 votes

step 1

Solve the first inequality


2x+3\leq5
\begin{gathered} 2x\leq5-3 \\ 2x\leq2 \\ x\leq1 \end{gathered}

the solution for the first inequality is the interval (-infinite,1]

step 2

Solve the second inequality

4x+1>17

4x>16

x>4

the solution for the second inequality is the interval (4, infinite)

therefore

the solution of the compound inequality is

(-infinite,1] U (4, infinite)

In a number line, the solution is

At x=1 is a closed circle and at x=4 is an open circle

Consider the following compound inequality. 2x+3_<5 or 4x+1>17A)Solve the inequality-example-1
User Yenni
by
5.1k points