Question

can someone please help me solve and graph this the past few have been incorrect and this is my homework and i really need help

Answer 1

step 1

Solve the inequality

`\begin{gathered} 3x+8\leq11 \\ 3x\leq11-8 \\ 3x\leq3 \\ x\leq1 \end{gathered}`

the solution for the first inequality is the interval

(-infinite, 1]

step 2

Solve the inequality

`\begin{gathered} 3x+8\text{ > 20} \\ 3x\text{ > 20-8} \\ 3x\text{ > 12} \\ x\text{ > 4} \end{gathered}`

the solution for the second inequality is the interval

(4, infinite)

step 3

the general solution for the first inequality or the second inequality is

(-infinite, 1] U (4, infinite)

see the attached figure to better understand the problem