Question

Length of carrier A is about how many football fields ?

Answer 1

Given:

The total length of carriers A and B, T=4198 feet.

The difference in lengths of the carriers is, D=10 feet.

The length of football field, L=100 yards.

Let a be the length of carrier A and b be the length of carrier B. It is given that carrier A is longer than carrier B.

Hence, the expression for the difference in lengths of the carriers can be written as,

`\begin{gathered} D=a-b \\ 10\text{ =a-b ----(1)} \end{gathered}`

The total length of carriers A and B can be written as,

`\begin{gathered} T=a+b \\ 4198=a+b\text{ ----(2)} \end{gathered}`

Add equations (1) and (2) to find the value of a.

`\begin{gathered} 2a=10+4198 \\ 2a=4208 \\ a=(4208)/(2) \\ a=2104\text{ f}eet \end{gathered}`

We know, 1 yard=3 feet.

So, 1 feet=(1/3) yard

The length of carrier A in yards is,

`a=2104\text{ f}eet*\frac{(1)/(3)\text{yard}}{\text{ 1 fe}et}=(2104)/(3)\text{yards}`

We know, the length of a football field is l=100 yards

Now, the ratio between a and l can be found as

`(a)/(l)=\frac{(2104)/(3)\text{ yards}}{100\text{ yards}}\cong7.0`

Hence, we can write

`a=7.0* l`

Since l is the length of a football field, the length of carrier A is about 7.0 football fields.