Factor the polynomial. 100b^2−49c^2

asked Mar 22, 2023 161k views

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Notice that:

$\begin{gathered} 100b^2=(10b)^2, \\ 49c^2=(7c)^2\text{.} \end{gathered}$

Therefore:

$100b^2-49c^2=(10b)^2-(7c)^2=(10b+7c)(10b-7c)\text{.}$

Answer:

$100b^2-49c^2=(10b+7c)(10b-7c)\text{.}$

Oldenborg answered Mar 27, 2023

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