Question

A 1,066 kg car moving at 86.55 km/h comes to a stop in 4.163 s.The magnitude of the net force on the can in Newtons is:

Answer 1

First, we find the acceleration of the car using the following formula.

`v_f=v_0+at`

Where the final speed is zero (because the car stops), the initial speed is 86.55 km/h, and the time is 4.163 seconds. Let's replace these magnitudes and solve for a.

`\begin{gathered} 0=86.55((km)/(h))+a\cdot4.163\sec \\ -86.55((km)/(h))=a\cdot4.163\sec \\ a=(-86.55((km)/(h)))/(4.163\sec ) \end{gathered}`

But, we have to transform the speed from km/h to m/s.

Then, we use this transformation to find the acceleration.

`\begin{gathered} a=(-24.04((m)/(s)))/(4.163\sec ) \\ a\approx5.77((m)/(s^2)) \end{gathered}`

Once we have the acceleration, we can use Newton's Second Law to find the net force.

`F=ma`

Let's replace the mass and acceleration to find F.

Therefore, the net force on the car is 6150.82 Newtons.