Question

How do find the vertex of a quadratic function using standard form

Answer 1

the standard form is:

`(y-k)^{}=4p(x-h)^2`

the vertex is (h,k)

if the quadratic function is not in the standard form we get

`f(x)=ax^2+bx+c`

the vertex is:

`(-(b)/(2a),f(-(b)/(2a)))`

and the symmetry axis is

`x=-(b)/(2a)`