Question

A student decreases the temperature of a 641 cm3 balloon from 435 K to 200 K.Assuming constant pressure, what should the new volume of the balloon be?Round your answer to one decimal place.Please help

Answer 1

The new volume of the balloon is 294 cm^3.

Step-by-step explanation:

The given information from the exercise is:

- Initial volume (V1): 641 cm^3

- Initial temperature (T1): 435 K

- Final temperature (T2): 200 K

To calculate the final volume (V2) of the balloon, we can use the Charles's law formula, by replacing the values of V1, T1 and T2:

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ (641cm^3)/(435K)=(V_2)/(200K) \\ 1.47(cm^3)/(K)=(V_(2))/(200K) \\ 1.47(cm^3)/(K)*200K=V_2 \\ 294cm^3=V_2 \end{gathered}`

So, the new volume of the balloon is 294 cm^3.