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For m>0, the expression (in the image) can be rewritten in the form 2m^a, where a is a fraction. Then a=___

For m>0, the expression (in the image) can be rewritten in the form 2m^a, where-example-1

2 Answers

2 votes

The calculated value of the variable a in the expression
\frac{2(\sqrt m)^3}{\sqrt[4]{m}} = 2m^a\\ is 5/4

How to determine the value of the expression a

From the question, we have the following parameters that can be used in our computation:


\frac{2(\sqrt m)^3}{\sqrt[4]{m}}

Also, we have that this expression equals


2m^a

So, we have


\frac{2(\sqrt m)^3}{\sqrt[4]{m}} = 2m^a\\

Divide both sides of the equation by 2


\frac{(\sqrt m)^3}{\sqrt[4]{m}} = m^a

This gives


(m^(3)/(2))/(m^(1)/(4)) = m^a

Applying the law of indices, we have


m^{(3)/(2) - (1)/(4)} = m^a

So, we have


a = (3)/(2) - (1)/(4)

Take the LCM and evaluate


a = (6 - 1)/(4)

Evaluate

a = 5/4

Hence, the value of a in the expression is 5/4

User Rich Seviora
by
4.1k points
6 votes

From the question;

we need to simplify


\frac{2(\sqrt[]{m})^3}{\sqrt[4]{m}}

In the form


2m^a

solving


\begin{gathered} \frac{2(\sqrt[]{m})^3}{\sqrt[4]{m}} \\ =\text{ }\frac{2(m^{(1)/(2)})^3}{m^{(1)/(4)}} \\ =\text{ }\frac{2m^{3\text{ }*(1)/(2)}}{m^{(1)/(4)}} \\ =\text{ }\frac{2m^{(3)/(2)}}{m^{(1)/(4)}} \\ \text{applying law of indices} \\ =2m^{(3)/(2)\text{ - }(1)/(4)} \\ =2m^{\frac{6\text{ - 1}}{4}} \\ =2m^{(5)/(4)} \end{gathered}

comparing the result


\begin{gathered} 2m^{(5)/(4)}=2m^a \\ \text{implies} \\ m^{(5)/(4)}=m^a \end{gathered}

Hence,

The value of a is


(5)/(4)

User Pallab Ganguly
by
3.8k points