To solve the exercise, we are going to complete the square, that is, we are going to find values c and d, such that these polynomials:

be perfect square trinomials.
These values are found like this:

Then the value c will be:

And the value d will be:

Now, rewriting the original equation:

Now, the equation of a circle in standard form is

Therefore, the equation of this circle in its standard form is

the radius is
![\begin{gathered} r=\sqrt[]{3} \\ \text{ Because} \\ r^2=(\sqrt[]{3})^2=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tjo4k24mwdwbc8372vcr7mg50swtf72ypp.png)
the coordinates of the center are

and the center is
