Question

This basketball season, Darius scored 4 more points than Ken, Devonte scored twice as many points as Ken,and Juwan scored 7 more than 5 times as many points as Ken. If all 4 players scored a total of 479 pointsthis season, how many points did each player score?Number of points scored by Ken:Number of points scored by Darius:Number of points scored by Devonte:Number of points scored by Juwan:

Answer 1

Let points scores by:

Darius be "d"

Ken be "k"

Devonte be "e"

Juwan be "j"

Now,

Darius scored 4 more than Ken, we can write:

d = 4 + k

Devonte scored twice as ken, we can write:

e = 2k

Juwan scored 7 more than 5 times ken, we can say:

j = 5k + 7

Four of them scored 479 total, we can write:

d + k + e + j = 479

Now, we have to solve all these 4 together and find our answer:

Putting the first 3 equations into last one we can solve for k:

`\begin{gathered} d+k+e+j=479 \\ 4+k+k+2k+5k+7=479 \\ 9k+11=479 \\ 9k=479-11 \\ 9k=468 \\ k=(468)/(9) \\ k=52 \end{gathered}`

Now,

d = 4 + k

d = 4 + 52

d = 56

and

e = 2k

e = 2(52)

e = 104

j = 5k + 7

j = 5(52) + 7

j = 267

So,

Darius = 56 points

Ken = 52 points

Devonte = 104 points

Juwan = 267 points