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Factor completely 16x2 − 25.

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Step-by-step explanation:

The question states that factor completely


16x^2-25

Concept:

To do this , we will use the principle of difference if tqo squares given below as


a^2-b^2=(a+b)(a-b)

Take the terms to be represented in terms of a and b below as


\begin{gathered} 16x^2=a^2 \\ (4x)^2=a^2 \\ a=4x \\ \\ 25=b^2 \\ b^2=5^2 \\ b=5 \end{gathered}

Hence,

By substituing the values, we will have


\begin{gathered} 16x^2-25=(4x)^2-5^2 \\ 16x^2-25=(4x-5)(4x+5) \end{gathered}

Hence,

The final answer is


\begin{equation*} (4x-5)(4x+5) \end{equation*}

User Cliff Hall
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