From the statement of the problem, we know that:
• Brian looks directly across and sees a pier,
,
• he walks downstream 400 ft, and looks at the pier again,
,
• he is now at an angle θ = 82°.
Using the data of the problem, we make the following diagram:
Where x is the distance across the river.
The diagram constitutes a triangle of:
• angle ,θ = 82°,,
,
• opposite side ,OC = 400 ft,,
,
• adjacent side ,AC = x,.
From trigonometry, we have the following trigonometric relation:
![\tan \theta=(OC)/(AC)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/1t9qynv01y5v7kff3xbsjvp50wtxxbns0q.png)
Replacing the data above in the last equation, we have:
![\tan (82^(\circ))=(400ft)/(x).](https://img.qammunity.org/2023/formulas/mathematics/college/fzanw2raqpi5ofvbi479l594904h8t1aar.png)
Solving for x the last equation, we find that:
![\begin{gathered} x\cdot\tan (82^(\circ))=400ft, \\ x=(400ft)/(\tan(82^(\circ))), \\ x\cong56.21633ft\cong56ft\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p7emmozk6dj3f0ghhrj3w29c6po160thyf.png)
Answer
The distance across the river is approximately 56 ft.