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Find the applied voltage of a circuit that draws 0.2 amperes through a 4800-ohmresistance

1 Answer

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  • Current=I=0.2A
  • Resistance=R=4800ohm

  • Voltage =V

Using ohms law.


\\ \sf\longmapsto (V)/(I)=R


\\ \sf\longmapsto V=IR


\\ \sf\longmapsto V=4800(0.2)


\\ \sf\longmapsto V=960V


\\ \sf\longmapsto V=0.96KV

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