We are given the following expression:
![1^3+2^2+3^1-4^0](https://img.qammunity.org/2023/formulas/mathematics/college/yt7unrmlcgems61utdtpro5sm3vhxlvz75.png)
The first term is 1 elevated to an exponent. Let's remember that 1 to any exponent is always 12, therefore, we have:
![1^3+2^2+3^1-4^0=1+2^2+3^1-4^0](https://img.qammunity.org/2023/formulas/mathematics/college/v6hsajridfid5906ycxrk2wvvihuxu4i3b.png)
Now we solve the second term which is 2 multiply by itself, therefore, we get:
![1+2^2+3^1-4^0=1+4+3^1-4^0](https://img.qammunity.org/2023/formulas/mathematics/college/1poudin6mj1ndsa1nw5arspdg5y4iy5jce.png)
The third term is 3 elevated to 1. Let's remember that any number elevated to 1 is the same number, therefore, we get:
![1+4+3^1-4^0=1+4+3-4^0](https://img.qammunity.org/2023/formulas/mathematics/college/jdsl5yattogvybdv7978mj7afws4fcm5b6.png)
The fourth term is 4 elevated to zero. Let's remember that any number elevated to zero is 1, therefore, we have:
![1+4+3-4^0=1+4+3-1](https://img.qammunity.org/2023/formulas/mathematics/college/owzym8umfizbours2mdbtzw6s38sgd5frq.png)
Solving the operations we get:
![1+4+3-1=7](https://img.qammunity.org/2023/formulas/mathematics/college/w9cgihlebhi0h40k22bn7hvmkcm2mqncxv.png)
Therefore, the expression simplifies to 7.