Question

Write the equation of a circle with the center K(7, 12) and passes through a point J(7, 10) ​

Answer 1

• (x - 7)² + (y - 12)² = 4

Explanation:

The center is K(7, 12)

Any point on the circle is connected with the center is the radius.

Since x-coordinates of the center and the given point are same, the radius is the difference of y- coordinates:

• r = 12 - 10 = 2

The equation:

• (x - 7)² + (y - 12)² = 2² ⇒ (x - 7)² + (y - 12)² = 4