1 Answer

Oleksandr Fedorenko · Answer 1 · 2023-09-05T20:49:39+0000

Given data

*The given angle is

$\theta=58.0^0$

*The distance traveled is R = 3.28 m

The formula for the horizontal range is given as

$R=(u^2\sin 2\theta)/(g)$

*Here g is the acceleration due to gravity

Substitute the values in the above expression as

$\begin{gathered} 3.28=(u^2\sin (2*58.0^0))/(9.8) \\ u=5.98\text{ m/s} \end{gathered}$

Thus, the initial velocity is u = 5.98 m/s

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