Question

The function (x, y) + (x - 3, y+5) is used to translate quadrilateral ABCD.The vertices of the quadrilateral are A(5,2), B(3,-1), C(-4,-2), andD(-1,6). Determine the distance the quadrilateral is translated.

Answer 1

The distance between any two points (x1,y1) and (x2,y2) can be determined by sqrt((x2-x1)^2+(y2-y1)^2)

In this case, any vertex is translated 3 units to left, on x coordinate, and 5 units up, on y coordinate.

Therefore, the distance the quadrilateral is translated is: sqrt((-3)^2+5^2) = sqrt(34) = 5.83 units.