Question

A fire truck is responding to an emergency. It accelerates from 0 to 66km/hr in 11 seconds. What is its rate of acceleration?13

Answer 1

We have the following:

In order to calculate it, it is essential that you know the acceleration formula

`a=(v_f-v_i)/(t_f-t_i)`

vi, is 0 km/h or km/s

vf, is 66 km/h or 66 km/h * 1 h/ 3600 s = 0.018 km/s

replacing:

`a=(0.018-0)/(11-0)=(0.018)/(11)=0.0031`

The rate of acceleration 0.0031 km/s^2 or 39600 km/h^2 (0.0031 km/s^2 * 3600^2 s^2/ 1 h^2)