Answer:
The vertex is (-3,1)
Explanation:
Here, we want to write the given function in the vertex form
Mathematically, we have this as;
y = a(x-h)^2 + k
where the vertex is (-h,k)
Thus, we have
Let us divide the coefficient of x by 2, square and add to both sides ; prior to this, we will equate y to 0
Thus, we have it that;
0 = x^2 + 6x + 10
x^2 + 6x + 10 + 9 = 9
x^2 + 6x + 9 = 9-10
x^2 + 6x + 9 = -1
(x + 3)^2 = -1
(x + 3)^2 + 1 = 0
So the vertex here as represented by (-h,k) is;
(-3,1)